$x^2+\frac{7}{4}x$
$\frac{dy}{dt}=yt+4t$
$2x-46+20x-7$
$\frac{3}{2}\cdot\frac{4}{9y^2b^4}$
$\left(-y^3\right)^4$
$\sqrt[2]{36x^2-72xy+36y^2}$
$\lim_{h\to0}\left(x\right)^2$
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