$\lim_{k\to\infty}\left(\frac{\sqrt{k}+\ln\left(k\right)}{k^2+1}\right)$
$-2<-x$
$5x^2+13x+6=0$
$-2\left(a+3\right)+2a$
$6x-5\ge9x+1$
$\left(10^2-4\right)\left(10+2\right)$
$3\:-\:\left(6\:-\:15\right)\:-\:\left(11\:-\:4\right)$
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