$\left(6x^6+x^8-4x^7-4x\right)^2$
$\frac{6}{4-x}\:,\:c=1$
$\frac{x^8+11x^4+20}{x^4+9}$
$\int\:\:\frac{x-1}{\sqrt{x^2-2x}}dx$
$17-6\cdot2$
$\csc\left(1.6\right)$
$\int_2^2\left(\frac{1}{x^2}\right)dx$
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