$\left(-9x^2\right)\left(\frac{3}{2}x^2\right)+\left(\frac{1}{2}x^3\right)\left(-18x\right)$

$\left(5+x^6\right)\frac{dy}{dx}=\frac{x^5}{y}$

$2x^7-4x^6-6x^5$

$-19-2\cdot\left(-2\right)$

$\frac{dy}{dx}=\left(xe^{x+3y}\right)$

$\frac{dy}{dx}=e^{2y-5x}$

$\int\frac{17x^3}{\sqrt{3+x^2}}dx$