$169-196z^4$
$\left(-1-a^2\right)^2$
$\int\frac{2x-3}{\left(x+1\right)\left(x^2+16\right)}dx$
$4-\ln z=1$
$\:\left(-1\right)\:+\:\left(-58\right)\:-\:10\:+\:2$
$-16t^2+70t+4=-5$
$t^2+t+1$
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