$\left(\frac{1}{2}x\right)+\left(\frac{2}{3}y\right)^2$

$\int\left(secx\right)^2tanxdx$

$\frac{1}{x-4}+\frac{1}{x+4}=\frac{16}{x^2-16}$

$\int\frac{2x}{3+2x}dx$

$\int\left(10e^{5x}\right)dx$

$2\cdot\left(5-6\right)-\left(7+\left(-1\right)\right)+\left(-2\right)$

$3\cdot1-2\cdot3+5-2-1$