$3\left(x-6\right)^2<108$
$\left(+6\right)-\left(-25\right)$
$\int\cos\left(\frac{1}{4}x\right)dx$
$\int_2^3e^{2x+3y}dx$
$\left(4+3\right)^2+5$
$x2+5x-25=0$
$2x^2+x+1=x^2-3x-3$
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