1+x2dy −1−y2dx=0\sqrt{1+x^2}dy\:-\sqrt{1-y^2}dx=01+x2dy−1−y2dx=0
∫1x2(x2+2)dx\int\frac{1}{x^2\left(x^2+2\right)}dx∫x2(x2+2)1dx
7(3)(−4)(2)(2)(2)7\left(3\right)\left(-4\right)\left(2\right)\left(2\right)\left(2\right)7(3)(−4)(2)(2)(2)
(23xy+12a2b3)3\left(\frac{2}{3}xy+\frac{1}{2}a^2b^3\right)^3(32xy+21a2b3)3
5(8h)5\left(8h\right)5(8h)
x−55x+10⋅2x+42x−10\frac{x-5}{5x+10}\cdot\frac{2x+4}{2x-10}5x+10x−5⋅2x−102x+4
64(m+n)364\left(m+n\right)^364(m+n)3
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