$17^3$
$\lim_{x\to0}\left(-x^2\cdot\ln\left(x^2\right)\right)$
$\frac{-4x}{3x-2}+1$
$3e+5e+e$
$\frac{1+\sec\:\left(4x\right)}{\sin\left(4x\right)+\tan\left(4x\right)}=\csc\left(4x\right)$
$120-31$
$y'=\sec^3x$
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