$\frac{dy}{dx}\left(\tan\left(y\right)=x^2y^2+2x\right)$
$\frac{x-2y}{2y}$
$\lim_{x\to\infty}\left(x^{0.5}\right)$
$\frac{8x^2-10x-3}{2x^2-7x-15}$
$\int\left(-9x^{2}+x+4\right)^{8}\left(-18x+1\right)dx$
$\tan^2\left(x\right)=\sec\left(x\right)\csc\left(x\right)\tan\left(x\right)-1$
$\left(7\sqrt{x}+4\right)x^2$
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