$\left(3x^3y^4+\right)\left(x+3\right)$
$1-\left(\frac{1}{x+1}\right)$
$\frac{4x-3}{12}+\frac{3x+4}{8}\ge1+\frac{5x}{6}$
$\left(mx-y+1\right)\left(x+my-2\right)$
$4x^{-3}y^3\cdot2y$
$\frac{9g}{g}$
$-\left(-3\left(a-b\right)+\frac{1}{3}\left(-6a-9b\right)\right)$
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