$5x^2+6x+1=0$
$\int\sec^{-1}\left(2x\right)dx$
$\left(x^2-3x\right)\cdot\left(x^3+1\right)$
$x+4\ge1$
$\frac{y}{2}+4\ge1$
$\lim_{x\to-\infty}\left(\frac{4x^2-8}{2x^2-13x}\right)$
$\ln\frac{6x\sqrt{1+5x}}{\left(x-3\right)^{11}}$
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