$\int_{-1}^12\left(x^5-3x\right)dx$
$\frac{dy}{dx}\left(x^4+2\right)^2\left(x^3+4\right)^4$
$\left(9x-7y\right)^3$
$q\:+\:13\:-\:6$
$\frac{cos}{cos-sin}=\frac{1}{1-tan}$
$\left(\frac{-393}{n^2+4n+3}-\left(-15\right)^{-n+2}\left(-3\right)^{n+1}\right)$
$-6\cdot51$
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