4x3−32=04x^3-32=04x3−32=0
∫(1+4x)dx\int\left(1+4x\right)dx∫(1+4x)dx
x2=1−4xx^2=1-4xx2=1−4x
∫−ππsin((4x+9π)18+3x)dx\int_{-\pi}^{\pi}\sin\left(\frac{\left(4x+9\pi\right)}{18}+3x\right)dx∫−ππsin(18(4x+9π)+3x)dx
dx−2ydy=0dx-2ydy=0dx−2ydy=0
(x+2)(x−1)(x−2)\left(x+2\right)\left(x-1\right)\left(x-2\right)(x+2)(x−1)(x−2)
(+9)−(−137)−(+23)\left(+9\right)-\left(-137\right)-\left(+23\right)(+9)−(−137)−(+23)
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!