$\frac{7x^4-4x^3+4}{x^3}$
$0=\frac{\tan\left(a\right)-1}{1+\tan\left(a\right)}$
$\sqrt{x}+\sqrt{x^5}-\sqrt{x^6}$
$\int\left(6x-7\right)\left(3x^2-7x\right)^5dx$
$x=2y+1$
$30^2-15^2+c$
$22-2x^2$
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