$\left(2x-5\right)\cdot\left(2x+5\right)-\left(2x-5\right)^2$
$\lim_{x\to-6}\left(x\right)$
$-5a-40$
$\lim_{x\to\infty}\left(\frac{4-x}{x+\sqrt[3]{1-x^3}}\right)$
$\lim_{x\to\infty}\left(\frac{\left(2x^2\right)}{e^{3x}}\right)$
$\left(-a^0\right)^5$
$x^2-3x\:-40$
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