$\left(2x-3y+6\right)^2$
$\left(-5x^2\right)\left(4x^2\right)$
$\frac{1}{\left(5x\right)^{-\frac{4}{3}}}$
$\frac{x-7}{2x^3-11x^2-16x-35}$
$\left(y^3+4\right)^2$
$1+a+6ab+6b$
$4n^2-32n=-4n^2-14$
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