$\frac{\left(9x^2+4x+1\right)}{\left(x^2+2x\right)}$
$x2+7x+18$
$xy^2+\left(x^2+1\right)y'=0$
$696\cdot08$
$\sin x=\left(0.3427\right)$
$\left(4x^3-1\right)\cdot\left(4x^3+1\right)$
$-\frac{385}{-55}$
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