$\sqrt[3]{40t^8}u^9$
$^{\circ}$
$\frac{6}{8}\cdot\frac{4}{3}$
$345,76-54,976$
$\lim_{x\to1}\:\:\left(3x\left(2x-1\right)\right)$
$y=\frac{5}{2}\left(\log6x^3-3x^2\right)$
$\frac{d}{dx}\frac{xe^y+ye^x}{siny}=4x$
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