$\left(x+8\right)^4$
$\int\tan\left(-x\right).\sec\left(-x\right)^2dx$
$\left(1-sen^2b\right)\left(1+tan^2b\right)=1$
$\left(3a+5\right)\left(3a-1\right)$
$\frac{dy}{dx}=\frac{e^x\left(y+8\right)}{4}$
$x^{10}+3x$
$\left(3a^3-7b^2\right)^2$
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