$\left(x+6\right)\left(x-2\right)\:-\:\left(x+4\right)\left(x+3\right)$
$\lim_{x\to0}\left(\frac{e^{-10x}-1}{5x}\right)$
$-1-2-\left(3-4-5-6\right)-7-8-9$
$\frac{1}{cot^2\left(x\right)+1}$
$\left(10\right)\left(-9\right)\left(-3\right)\left(-11\right)$
$\left(3n+4\right)^3$
$3t+2t^2$
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