$\int\frac{x^3}{\sqrt[5]{6+x^4}}dx$
$\frac{x^2+3x+2}{x-1}$
$\frac{7}{8}x+3<=12$
$\left(3x^3+5x^2-x\right)-\left(7x^3+8x-3\right)$
$\frac{-\infty^3}{2\left(\infty\right)^2-4}$
$\frac{x+2}{3}+\frac{4x+1}{2}$
$9x^2+30ax+25a^2$
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