$4a^3-3b^2+\frac{1}{5}a^2b+6ab^2-2\left(a=2;b=5\right)$
$\frac{\left[tanx+secx\right]}{sec\left[1+\frac{tanx}{secx}\right]}=1$
$\left(2f-5g\right)^2$
$a+3=3$
$a^2b^3y^4-625a^2b^3$
$\lim_{x\to0}\left(\frac{3x+\sin\left(x\right)}{2x}\right)$
$6a-\left(-2^4\right)$
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