$x^3+3x^2+4x$
$x\:sin\left(\frac{y}{x}\right)\left(y\right)^'=ysin\left(\frac{y}{x}\right)+x$
$8\left(-11\right)$
$-7^5$
$\left(c-7\right)^2$
$\left(y\right)^'-\frac{y}{x}=x^4$
$x\frac{dy}{dx}+y=x^4y^4$
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