$1+28+29+-40$
$\frac{\left(2x^2-23+66\right)}{\left(2x^2+x+1\right)}$
$4y^2+24y^2+36$
$tan\left(\theta\:-\pi\:\right)=tan\left(\theta\:\right)$
$-5x^{2}+5\left(5x-4\right)$
$\left(x+5\right)\left(x-5\right)$
$\frac{4^2\cdot2^{-4}}{2^{-8}}$
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