$\frac{d^4}{dx^4}\:x^3$
$\sqrt[3]{\left(x+6\right)^2-\left(x+3\right)^2-6x}$
$624\cdot\frac{1}{4}$
$\frac{x^3-y^3}{x-4}$
$4\sin^3\left(2x\right)-1=0$
$6x+9<63$
$\left(2a^2-6b\right)^2$
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