$x^2+\frac{1}{4}x=0$

$2x-13=9+4z$

$f\left(4\right)=\frac{4\left(4\right)-10}{\left(4\right)-2}$

$x^2-24x+16$

$\lim_{x\to0}\left(\left(\frac{x^2\left(x+7\right)^2}{\left(2x^3+7\right)}\right)\right)$

$\left(x^2+1\right)y''+y'-x^2y$

$\left(9x^4-2y^3\right)\left(9x^4+2y^3\right)$