$\frac{3x^3-2x^2+6x-4}{x-5}$
$\frac{x+y}{y}$
$\int\frac{\left(4x^2-8x\right)}{\left(x-1\right)^2\cdot\left(x^2+1\right)}dx$
$\frac{4}{x}=\frac{x-1}{5}$
$\left(3a^2+5\right)\left(3a^2-5\right)$
$-3y+7y+4y^3-2y^2+6y^3-7y^3-5y$
$35:-5$
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