$5a+4a-2a+7-3a$
$\left(\frac{\left(\sqrt{h^5}\right)}{\sqrt[6]{h^3}}\right)^4\:\:$
$3a^2+a^2+b$
$2x^2\:+\:x\:-\:3x^5\:+\:4x^8$
$\left(x-7x\right)^3$
$\frac{96}{16}$
$4 x ^ { 2 } - 8 x ^ { 2 } - 6 x ^ { 2 } + 2 x ^ { 2 } - 6 x + 10$
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