$\tan\left(x\right)=\frac{73.3}{45.0}$
$\frac{3x\:+5}{2x^2-3x-9}$
$\frac{dy}{dx}\left(12x^4y^2-7xy^3=4-8y\right)$
$42\::\:-21\:=\:$
$\frac{a^3+8}{a^2-4a+4}.\frac{a^3-64}{a^2+4a+4}$
$2x\:-\:3y+7z\:-5x\:-2y+z$
$\left(3x^2+2\right)\sin\left(x\right)$
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