$\frac{x}{4}-\frac{1}{3}$
$6x^2+5x+4$
$\lim_{x\to\infty}\left(\frac{6x-3}{5x^2+1}\right)$
$f\left(x\right)=\frac{x^{5}\left(x-5\right)^{6}}{\left(x^{2}+5\right)^{8}}$
$\frac{dx}{dt}=-xt$
$\frac{dy}{dt}+2ty=0$
$\left(-5m+6\right)+\left(-m+5\right)$
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