$7^{-3}\cdot7^6$
$\frac{d}{dx}\left(\arcsec\left(2x^2+3\right)\right)$
$\left(x\:+\:6\right)\left(4x\:-\:5y\right)$
$-10x^2+7x+25\le0$
$5\left(53\right)+2$
$\int\frac{3}{4x-6}dx$
$23.15-7.30$
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