$\frac{du}{dt}=\frac{8+t^4}{ut^2-u^4t^2}$
$-7y^2-12y+4$
$-2x\:-\:5x\:-\:9x$
$\int\:\int\:\frac{x+1}{\left(x-3\right)^2}dx$
$\lim_{x\to0}\left(\frac{\ln\left(\sec\left(2x\right)\right)}{x^2}\right)$
$\frac{dy}{dx}\left(y=u^2+1\right)$
$z^2-16z+8$
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