(−3x3+x2+1)⋅(x+1)\left(-3x^3+x^2+1\right)\cdot\left(x+1\right)(−3x3+x2+1)⋅(x+1)
6a218ab\frac{6a^2}{18ab}18ab6a2
6x≤126x\le126x≤12
∫(0.11+0.01x)1+xdx\int\frac{\left(0.11+0.01x\right)}{1+x}dx∫1+x(0.11+0.01x)dx
3x2−35x−12=03x^2-35x-12=03x2−35x−12=0
ddxy2=8px\frac{d}{dx}y^2=8pxdxdy2=8px
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