$4\le4f-4$
$3\cos x+\sqrt{2}=\cos x$
$\frac{\frac{1}{2}a^2}{5a^3}$
$\:\left(10x-5\right)\left(10x-4\right)$
$-3sinx=cos2x$
$\left(+5\right)-\left(+8\right)+\left(-3\right)-\left(-4\right)\:$
$\frac{x-5}{x^2-3x-4}$
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