$\frac{\left(3x-3x^2\right)}{-3+3x}$
$\:\:6x^3-11x^2+4x$
$\lim_{n\to\infty}\left(\frac{n}{\ln\left(n\right)}\right)$
$\int x^5\cdot\sec^2\left(x^3\right)dx$
$\int-9x^{-1}\left(5x^3-6x^2-8\right)dx$
$45\cdot11$
$5^2-1^{10}$
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