Solve the inequality -3-3x<-2xy^2(1-b)+3x-y

 Exercise

$-3\-3x<\left[-2xy^2\left(1-b\right)+3x-y\\right]$

 

Solve the product $-2xy^2\left(1-b\right)$

$-3-3x<\left(-2+2b\right)xy^2+3x-y$

 

Multiplying polynomials $x$ and $-2+2b$

$-3-3x<\left(-2x+2xb\right)y^2+3x-y$

 

Multiply the single term $y^2$ by each term of the polynomial $\left(-2x+2xb\right)$

$-3-3x<-2xy^2+2xby^2+3x-y$

 

Moving the term $-3$ to the other side of the inequation with opposite sign

$-3x<-2xy^2+2xby^2+3x-y+3$

 

Divide both sides of the inequation by $-3$

$x<\frac{-2xy^2+2xby^2+3x-y+3}{-3}$

$x<\frac{-2xy^2+2xby^2+3x-y+3}{-3}$

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