$$\frac{d^3}{dx^3}\left(\frac{1}{3x+6}\right)$$

$$w^2+10w+10$$

$$p=\frac{1}{\tan\alpha-\sec\alpha}+\frac{1}{\tan\alpha+\sec\alpha}$$

$$49m^2+14+1$$

$$\frac{dw}{dt}=x^2+y^2+z^2\:$$

$$\frac{2}{\left(x+h\right)^2-3}-\frac{2}{x^2-3}$$

$$\left(6y^2\right)+4y^2+\left(-12y^2\right)+y-6$$