$3^3+6^2+2^2$
$\int\:\frac{x+1}{\left(x-3\right)^2}\:dx$
$\left(4a-9b\right)\left(3b\right)$
$\left|-2-3\right|$
$\left(2\right)\left(4x^2\right)\left(x\right)$
$\lim_{x\to-\infty}\left(-2x^5-8x^4+7x^3-10\right)$
$\frac{d^2}{dx^2}\left(\frac{x+5}{x}\right)$
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