$\frac{dy}{dx}\left(x^4y^2-x^3+2xy^3=0\right)$
$\left(s+2\right)^4$
$\left(x^2+y^3\right)^5$
$\lim_{x\to2}\sqrt{3x^2+4}$
$\left(2x+3y\:-4\right)\:-\:\left(5x+2\:\right)$
$y^2-4y=4y+16$
$c^8.c^3=c^4.c^x$
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