$8\:\cdot\:\left(-1\right)\:\cdot\left(-2\right)\:\cdot\:5$

$\lim_{x\to-\infty}\left(\frac{x^6+x^3+x}{x^4-x^2+1}\right)$

$\int\left(x+7\right)^2\:dx$

$x^2=64$

$\frac{5x-1}{x^2-4}+\frac{3}{x+2}-\frac{2}{x-2}$

$\left(2.1x+5.3\right)^3$

$\left(\sec^2\left(x\right)-1\right)\frac{1}{\sec^2\left(x\right)}$