$\left(-43\right)-\left(-36\right)$
$0.045\cdot10^2$
$-2x^3\left(3x^2-1\right)+\left(3x^2-1\right)\left(2x^3+5\right)-5\left(3x^2+1\right)$
$x^3-2x^2-4x+8$
$\left(x-3\right)\left(2x+1\right)$
$\left(2\sqrt{x}-3\right)\left(5\sqrt{x}+8\right)$
$\frac{x}{14}=\frac{9}{7}$
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