$\ln\left(2x^2\right)-\ln\left(2\right)=2$
$\lim_{x\to-3}\left(\frac{2x^2+5x+3}{x^2-x-6}\right)$
$\left(-6x^2-6x-3\right)^2$
$\left(-6\right)+\sqrt[3]{27}$
$5\left(-7p+1\right)$
$\int\frac{nb}{x^2-4}dx$
$b^2+7b+12$
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