$\lim_{x\to-\infty}\left(\frac{\sqrt{4x^6-x}}{x^3\:+\:8\:}\right)$
$\frac{x+2}{x+3}=\frac{-4}{x+2}$
$6\cdot2-1$
$\frac{-v}{3v-8}=\frac{1}{v-10}$
$y'=3x$
$a^4+6y+9^2$
$\left(x-3\right)^2\left(y-4\right)^2$
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