$3x-4\le8$
$\frac{dy}{dx}=\frac{\left[\left(y+1\right)\left(y+3\right)\right]}{x^2-8x+5}$
$\left(13.4\right)\left(\frac{1}{22.3}\right)\left(\frac{2.00}{1}\right)$
$4x^2+10x+4=0$
$\left(8c^5d^2+5x^8y\right)^2$
$\frac{2zx^3}{6xvy}$
$16a+72$
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