$\ln\left(x^2\right)+\ln\left(x\right)=3$
$\frac{\sin\infty.\cos\infty}{\cos^2\infty-\sin^2\infty}=\frac{\tan\infty}{1-\tan^2\infty}$
$\frac{dy}{dx}=lnt+4t$
$\frac{x^2-9x+16}{x-3}$
$5z\left(3z-9\right)$
$-4b-3b$
$\frac{dy}{dx}=\frac{5x}{y},y\left(1\right)=-2$
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