$4x-3=-5x+6$
$-48\cdot\left(-3\right)$
$\frac{x}{2}\left(\frac{1}{3}x+\frac{1}{2}y\right)$
$\left(4x+y\right)\left(xy-4\right)^3$
$x'=x^3$
$-7-1-3y-10y$
$\int ( 3 x - 20 ) ^ { 10 } d x$
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