$$121x^2-4=0$$

$$\lim_{x\to\infty}\left(\frac{4ln\left(t+3\right)}{\sqrt[5]{t}}\right)$$

$$\left(3x^5-1\right)\left(3x^5+4\right)$$

$$\left(3y+3y+3z\right)^3$$

$$5^{1-2}$$

$$16a^2+40ab+25ab^2$$

$$\frac{dp}{dt}=8p\left(1-\frac{p}{50}\right)-2\left(lm\left(5+t^2\right)\right)$$