Simplifying
$\left(\frac{a^{-2}b}{a^3b^{-4}}\right)^{-3}+\left(\frac{ab^{-1}}{a^3b^2}\right)^5$
$-7-\left(-12\right)-3$
$\int_{-1}^1e^x\:dx$
$x^2\ge\:4x+12$
$y^{\prime}=x\left(y^{2}+1\right)$
$\left(\:2-3n\right)\left(2+3n\right)$
$\left(9x\right)\cdot\left(-6x^2-5x^4+8x\right)$
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