$\:b\:+\:7.9\:=\:16$
$\frac{d^2}{dx^2}\left(5x^5+3x^4\right)$
$\left(\frac{x^3}{y^{-2}}\right)^{-3}$
$\frac{\sec^2\left(x\right)}{\cot^2\left(x\right)+1}$
$x^{3}+3x^{2}-4$
$3\left(x-1\right)^2=0$
$0x\:\left(-7\right)$
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